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Trigonometry – Basics and Ratios

🔹 What is Trigonometry?

Trigonometry is the branch of mathematics that deals with the relationships between the sides and angles of triangles, especially right-angled triangles.

It helps solve problems related to heights, distances, and angles.

🔹 Right-Angled Triangle Basics

  • A triangle with one angle equal to 90°.

  • Sides are named relative to the angle of interest:

    • Hypotenuse (H): The longest side opposite the right angle.

    • Opposite side (O): Side opposite to the angle considered.

    • Adjacent side (A): Side next to the angle considered (other than hypotenuse).

🔹Trigonometric Ratios

For an angle θ in a right triangle:

RatioFormulaMeaning
Sin θOH\frac{O}{H}Sine = Opposite / Hypotenuse
Cos θAH\frac{A}{H}Cosine = Adjacent / Hypotenuse
Tan θOA\frac{O}{A}Tangent = Opposite / Adjacent
Cosec θHO\frac{H}{O}Cosecant = Hypotenuse / Opposite
Sec θHA\frac{H}{A}Secant = Hypotenuse / Adjacent
Cot θAO\frac{A}{O}Cotangent = Adjacent / Opposite

🔹Trigonometry Table

θ (Degrees) θ (Radians) sin θ cos θ tan θ cot θ sec θ cosec θ
0 0 1 0 1
30° π/6 1/2 √3/2 1/√3 √3 2/√3 2
45° π/4 1/√2 1/√2 1 1 √2 √2
60° π/3 √3/2 1/2 √3 1/√3 2 2/√3
90° π/2 1 0 0 1
180° π 0 –1 0 –1
270° 3π/2 –1 0 0 –1

🔹Important Trigonometric Identities

  • sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1

  • 1+tan2θ=sec2θ1 + \tan^2 \theta = \sec^2 \theta

  • 1+cot2θ=csc2θ1 + \cot^2 \theta = \csc^2 \theta

  • tanθ=sinθcosθ\tan \theta = \frac{\sin \theta}{\cos \theta}

  • cotθ=1tanθ\cot \theta = \frac{1}{\tan \theta}


🔹 Common Angle Values (in degrees and radians)

θ (degrees)30°45°60°90°
Sin θ01/2√2/2√3/21
Cos θ1√3/2√2/21/20
Tan θ0√3/31√3


🔹Using Trigonometry to Solve Problems

  • Use Pythagoras theorem to find missing sides:
    H2=O2+A2H^2 = O^2 + A^2

  • Use trigonometric ratios to find unknown sides or angles.

  • Remember the angle of elevation and depression concepts:

    • Elevation: angle above the horizontal line.

    • Depression: angle below the horizontal line.

🔹 Examples

Example 1:
In a right triangle, if the hypotenuse is 10 cm and the angle θ = 30°, find the opposite side.

Solution:
sin30°=O10\sin 30° = \frac{O}{10}
1/2=O10O=5 cm1/2 = \frac{O}{10} \Rightarrow O = 5 \text{ cm}

Example 2:

If tan θ = 1, find sin θ and cos θ.

✅ Solution:

Given:
tan θ = 1 ⇒ Opposite side = Adjacent side

Let both the opposite and adjacent sides be 1 unit.

Then using the Pythagoras Theorem:

Hypotenuse = √(Opposite² + Adjacent²)
= √(1² + 1²)
= √2

Now calculate:

  • sin θ = Opposite / Hypotenuse = 1 / √2 = √2⁄2

  • cos θ = Adjacent / Hypotenuse = 1 / √2 = √2⁄2

✅ Final Answer:
sin θ = √2⁄2
cos θ = √2⁄2

🔹Common Mistakes to Avoid

  • Confusing adjacent and opposite sides for the given angle.

  • Using degrees when radians are required, or vice versa.

  • Forgetting to simplify square roots.

  • Assuming the triangle is right-angled without confirmation.

🔹 Practice Questions

  1. In a right triangle, if the opposite side is 7 cm and the adjacent side is 24 cm, find tanθ\tan \theta.

  2. Calculate sin45\sin 45^\circ, cos60\cos 60^\circ, and tan30\tan 30^\circ.

  3. Find the hypotenuse if sinθ=0.6\sin \theta = 0.6 and the opposite side is 9 cm.

  4. A ladder leans against a wall making a 60° angle with the ground. If the ladder is 10 m long, find the height reached on the wall.

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